Fig. 4From: Infinitely long branches and an informal test of common ancestryAIC and BIC per site if we align independently each subset (B and E sequences under IO, and B+E sequences under UCA). Each Δ I C (where IC = AIC or BIC) is calculated as Δ I C=I C(B)+I C(E)−I C(B+E) such that positive values favour UCA. The Δ I C values were further divided by the alignment length under UCA, to give scaled values comparable with other analysesBack to article page